Solve {c}{245/90}{-8/10}{10/10}

$$\left. \begin{array} { c } { 2 \frac { 45 } { 90 } } \\ { \frac { - 8 } { 10 } } \\ { \frac { 10 } { 10 } } \end{array} \right.$$

Sort

$$-\frac{4}{5},1,\frac{5}{2}$$

Solution Steps

Divide 10 by 10 to get 1.

$$sort(\frac{2\times 90+45}{90},\frac{-8}{10},1)$$

Multiply 2 and 90 to get 180.

$$sort(\frac{180+45}{90},\frac{-8}{10},1)$$

Add 180 and 45 to get 225.

$$sort(\frac{225}{90},\frac{-8}{10},1)$$

Reduce the fraction \frac{225}{90} to lowest terms by extracting and canceling out 45.

$$sort(\frac{5}{2},\frac{-8}{10},1)$$

Reduce the fraction \frac{-8}{10} to lowest terms by extracting and canceling out 2.

$$sort(\frac{5}{2},-\frac{4}{5},1)$$

Convert decimal numbers in the list \frac{5}{2},-\frac{4}{5},1 to fractions.

$$\frac{5}{2},-\frac{4}{5},1$$

Least common denominator of the numbers in the list \frac{5}{2},-\frac{4}{5},1 is 10. Convert numbers in the list to fractions with denominator 10.

$$\frac{25}{10},-\frac{8}{10},\frac{10}{10}$$

To sort the list, start from a single element \frac{25}{10}.

$$\frac{25}{10}$$

Insert -\frac{8}{10} to the appropriate location in the new list.

$$-\frac{8}{10},\frac{25}{10}$$

Insert \frac{10}{10} to the appropriate location in the new list.

$$-\frac{8}{10},\frac{10}{10},\frac{25}{10}$$

Replace the obtained fractions with the initial values.

$$-\frac{4}{5},1,\frac{5}{2}$$

Evaluate

$$\frac{5}{2},\ -\frac{4}{5},\ 1$$