Solve {c}{12x+y=96}{(x+19/4)*16=320}

$$\left. \begin{array} { c } { 12 x + y = 96 } \\ { ( x + \frac { 19 } { 4 } ) \cdot 16 = 320 } \end{array} \right.$$

Solve for x, y

$$x = \frac{61}{4} = 15\frac{1}{4} = 15.25$$

$$y=-87$$

Solution Steps

Consider the second equation. Divide both sides by 16.

$$x+\frac{19}{4}=\frac{320}{16}$$

Divide 320 by 16 to get 20.

$$x+\frac{19}{4}=20$$

Subtract \frac{19}{4} from both sides.

$$x=20-\frac{19}{4}$$

Subtract \frac{19}{4} from 20 to get \frac{61}{4}.

$$x=\frac{61}{4}$$

Consider the first equation. Insert the known values of variables into the equation.

$$12\times \frac{61}{4}+y=96$$

Multiply 12 and \frac{61}{4} to get 183.

$$183+y=96$$

Subtract 183 from both sides.

$$y=96-183$$

Subtract 183 from 96 to get -87.

$$y=-87$$

The system is now solved.

$$x=\frac{61}{4} y=-87$$