Solve {c}{13/8-31/4}{0}

$$\left. \begin{array} { c } { 1 \frac { 3 } { 8 } - 3 \frac { 1 } { 4 } } \\ { 0 } \end{array} \right.$$

Sort

$$-\frac{15}{8},\ 0$$

Solution Steps

Multiply 1 and 8 to get 8.

$$sort(\frac{8+3}{8}-\frac{3\times 4+1}{4},0)$$

Add 8 and 3 to get 11.

$$sort(\frac{11}{8}-\frac{3\times 4+1}{4},0)$$

Multiply 3 and 4 to get 12.

$$sort(\frac{11}{8}-\frac{12+1}{4},0)$$

Add 12 and 1 to get 13.

$$sort(\frac{11}{8}-\frac{13}{4},0)$$

Least common multiple of 8 and 4 is 8. Convert \frac{11}{8} and \frac{13}{4} to fractions with denominator 8.

$$sort(\frac{11}{8}-\frac{26}{8},0)$$

Since \frac{11}{8} and \frac{26}{8} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{11-26}{8},0)$$

Subtract 26 from 11 to get -15.

$$sort(-\frac{15}{8},0)$$

Convert decimal numbers in the list -\frac{15}{8},0 to fractions.

$$-\frac{15}{8},0$$

Evaluate

$$-\frac{15}{8},\ 0$$