Solve {c}{0.79(40)^3-27(40)^2-885(40)+37800}{1970+40}

$$\left. \begin{array} { c } { 0.79 ( 40 ) ^ { 3 } - 27 ( 40 ) ^ { 2 } - 885 ( 40 ) + 37800 } \\ { 1970 + 40 } \end{array} \right.$$

Sort

$$2010,9760$$

Solution Steps

Calculate 40 to the power of 3 and get 64000.

$$sort(0.79\times 64000-27\times 40^{2}-885\times 40+37800,1970+40)$$

Multiply 0.79 and 64000 to get 50560.

$$sort(50560-27\times 40^{2}-885\times 40+37800,1970+40)$$

Calculate 40 to the power of 2 and get 1600.

$$sort(50560-27\times 1600-885\times 40+37800,1970+40)$$

Multiply 27 and 1600 to get 43200.

$$sort(50560-43200-885\times 40+37800,1970+40)$$

Subtract 43200 from 50560 to get 7360.

$$sort(7360-885\times 40+37800,1970+40)$$

Multiply 885 and 40 to get 35400.

$$sort(7360-35400+37800,1970+40)$$

Subtract 35400 from 7360 to get -28040.

$$sort(-28040+37800,1970+40)$$

Add -28040 and 37800 to get 9760.

$$sort(9760,1970+40)$$

Add 1970 and 40 to get 2010.

$$sort(9760,2010)$$

To sort the list, start from a single element 9760.

$$9760$$

Insert 2010 to the appropriate location in the new list.

$$2010,9760$$

Evaluate

$$9760,\ 2010$$