Solve {c}{0x+25y=5}{x+y=130}

$$\left. \begin{array} { c } { 0 x + 25 y = 5 } \\ { x + y = 130 } \end{array} \right.$$

Solve for x, y

$$x = \frac{649}{5} = 129\frac{4}{5} = 129.8$$

$$y=\frac{1}{5}=0.2$$

Solution Steps

Consider the first equation. Anything times zero gives zero.

$$0+25y=5$$

Anything plus zero gives itself.

$$25y=5$$

Divide both sides by 25.

$$y=\frac{5}{25}$$

Reduce the fraction \frac{5}{25} to lowest terms by extracting and canceling out 5.

$$y=\frac{1}{5}$$

Consider the second equation. Insert the known values of variables into the equation.

$$x+\frac{1}{5}=130$$

Subtract \frac{1}{5} from both sides.

$$x=130-\frac{1}{5}$$

Subtract \frac{1}{5} from 130 to get \frac{649}{5}.

$$x=\frac{649}{5}$$

The system is now solved.

$$x=\frac{649}{5} y=\frac{1}{5}$$