Solve {c}{.1135+.36+.25c=8195}{b=c+40000}

$$\left. \begin{array} { c } { .1135 + .36 + .25 c = 8195 } \\ { b = c + 40000 } \end{array} \right.$$

Solve for c, b

$$c=32778.106$$

$$b=72778.106$$

Solution Steps

Consider the first equation. Add 0.1135 and 0.36 to get 0.4735.

$$0.4735+0.25c=8195$$

Subtract 0.4735 from both sides.

$$0.25c=8195-0.4735$$

Subtract 0.4735 from 8195 to get 8194.5265.

$$0.25c=8194.5265$$

Divide both sides by 0.25.

$$c=\frac{8194.5265}{0.25}$$

Expand \frac{8194.5265}{0.25} by multiplying both numerator and the denominator by 10000.

$$c=\frac{81945265}{2500}$$

Reduce the fraction \frac{81945265}{2500} to lowest terms by extracting and canceling out 5.

$$c=\frac{16389053}{500}$$

Consider the second equation. Insert the known values of variables into the equation.

$$b=\frac{16389053}{500}+40000$$

Add \frac{16389053}{500} and 40000 to get \frac{36389053}{500}.

$$b=\frac{36389053}{500}$$

The system is now solved.

$$c=\frac{16389053}{500} b=\frac{36389053}{500}$$