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Solve for a, b, c
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a=\frac{24}{59}b+\frac{150}{59}
Solve -14.75a+6b=-37.5 for a.
3\left(\frac{24}{59}b+\frac{150}{59}\right)-8b=32.5
Substitute \frac{24}{59}b+\frac{150}{59} for a in the equation 3a-8b=32.5.
b=-\frac{587}{160} c=\frac{1}{2}b+\frac{13}{4}
Solve the second equation for b and the third equation for c.
c=\frac{1}{2}\left(-\frac{587}{160}\right)+\frac{13}{4}
Substitute -\frac{587}{160} for b in the equation c=\frac{1}{2}b+\frac{13}{4}.
c=\frac{453}{320}
Calculate c from c=\frac{1}{2}\left(-\frac{587}{160}\right)+\frac{13}{4}.
a=\frac{24}{59}\left(-\frac{587}{160}\right)+\frac{150}{59}
Substitute -\frac{587}{160} for b in the equation a=\frac{24}{59}b+\frac{150}{59}.
a=\frac{21}{20}
Calculate a from a=\frac{24}{59}\left(-\frac{587}{160}\right)+\frac{150}{59}.
a=\frac{21}{20} b=-\frac{587}{160} c=\frac{453}{320}
The system is now solved.