Solve {c}{-12y=6}{3x+2y=11}

$$\left. \begin{array} { c } { - 12 y = 6 } \\ { 3 x + 2 y = 11 } \end{array} \right.$$

Solve for y, x

$$x=4$$

$$y=-\frac{1}{2}=-0.5$$

Solution Steps

Consider the first equation. Divide both sides by -12.

$$y=\frac{6}{-12}$$

Reduce the fraction \frac{6}{-12} to lowest terms by extracting and canceling out 6.

$$y=-\frac{1}{2}$$

Consider the second equation. Insert the known values of variables into the equation.

$$3x+2\left(-\frac{1}{2}\right)=11$$

Multiply 2 and -\frac{1}{2} to get -1.

$$3x-1=11$$

Add 1 to both sides.

$$3x=11+1$$

Add 11 and 1 to get 12.

$$3x=12$$

Divide both sides by 3.

$$x=\frac{12}{3}$$

Divide 12 by 3 to get 4.

$$x=4$$

The system is now solved.

$$y=-\frac{1}{2} x=4$$