Solve {c}{sqrt{9*7+1}}{(5+3)^2}

$$\left. \begin{array} { c } { \sqrt { 9 \times 7 + 1 } } \\ { ( 5 + 3 ) ^ { 2 } } \end{array} \right.$$

Sort

$$8,\ 64$$

Solution Steps

Multiply 9 and 7 to get 63.

$$sort(\sqrt{63+1},\left(5+3\right)^{2})$$

Add 63 and 1 to get 64.

$$sort(\sqrt{64},\left(5+3\right)^{2})$$

Calculate the square root of 64 and get 8.

$$sort(8,\left(5+3\right)^{2})$$

Add 5 and 3 to get 8.

$$sort(8,8^{2})$$

Calculate 8 to the power of 2 and get 64.

$$sort(8,64)$$

The list values are already in order.

$$8,64$$

Evaluate

$$8,\ 64$$