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\frac{9}{7}\times \frac{9}{3\sqrt{3}}
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
\frac{9}{7}\times \frac{9\sqrt{3}}{3\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{9}{3\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
\frac{9}{7}\times \frac{9\sqrt{3}}{3\times 3}
The square of \sqrt{3} is 3.
\frac{9}{7}\sqrt{3}
Cancel out 3\times 3 in both numerator and denominator.