Solve {c}{121/132-70/180}{55quad2}

$$\left. \begin{array} { c } { \frac { 121 } { 132 } - \frac { 70 } { 180 } } \\ { 55 \quad 2 } \end{array} \right.$$

Sort

$$\frac{19}{36},\ 552$$

Solution Steps

Reduce the fraction \frac{121}{132} to lowest terms by extracting and canceling out 11.

$$sort(\frac{11}{12}-\frac{70}{180},552)$$

Reduce the fraction \frac{70}{180} to lowest terms by extracting and canceling out 10.

$$sort(\frac{11}{12}-\frac{7}{18},552)$$

Least common multiple of 12 and 18 is 36. Convert \frac{11}{12} and \frac{7}{18} to fractions with denominator 36.

$$sort(\frac{33}{36}-\frac{14}{36},552)$$

Since \frac{33}{36} and \frac{14}{36} have the same denominator, subtract them by subtracting their numerators.

$$sort(\frac{33-14}{36},552)$$

Subtract 14 from 33 to get 19.

$$sort(\frac{19}{36},552)$$

Convert decimal numbers in the list \frac{19}{36},552 to fractions.

$$\frac{19}{36},552$$

Evaluate

$$\frac{19}{36},\ 552$$