Solve left(x+1right)left(x^2-x+1right)-xleft(x+3right)left(x-3right)=10

$$\left( x+1 \right) \left( { x }^{ 2 } -x+1 \right) -x \left( x+3 \right) \left( x-3 \right) = 10$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+1 by x^{2}-x+1 and combine like terms.

$$x^{3}+1-x\left(x+3\right)\left(x-3\right)=10$$

Use the distributive property to multiply x by x+3.

$$x^{3}+1-\left(x^{2}+3x\right)\left(x-3\right)=10$$

Use the distributive property to multiply x^{2}+3x by x-3 and combine like terms.

$$x^{3}+1-\left(x^{3}-9x\right)=10$$

To find the opposite of x^{3}-9x, find the opposite of each term.

$$x^{3}+1-x^{3}+9x=10$$

Combine x^{3} and -x^{3} to get 0.

$$1+9x=10$$

Subtract 1 from both sides.

$$9x=10-1$$

Subtract 1 from 10 to get 9.

$$9x=9$$

Divide both sides by 9.

$$x=\frac{9}{9}$$

Divide 9 by 9 to get 1.

$$x=1$$