Solve left(3-2x^2+7xright)+(-6+2x^2-5x)

$$\left( 3-2 { x }^{ 2 } +7x \right) +(-6+2 { x }^{ 2 } -5x)$$

Evaluate

$$2x-3$$

Solution Steps

Subtract 6 from 3 to get -3.

$$-3-2x^{2}+7x+2x^{2}-5x$$

Combine -2x^{2} and 2x^{2} to get 0.

$$-3+7x-5x$$

Combine 7x and -5x to get 2x.

$$-3+2x$$

Differentiate w.r.t. x

$$2$$

Steps Using Derivative Rule for Sum

Subtract 6 from 3 to get -3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3-2x^{2}+7x+2x^{2}-5x)$$

Combine -2x^{2} and 2x^{2} to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3+7x-5x)$$

Combine 7x and -5x to get 2x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3+2x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$2x^{1-1}$$

Subtract 1 from 1.

$$2x^{0}$$

For any term t except 0, t^{0}=1.

$$2\times 1$$

For any term t, t\times 1=t and 1t=t.

$$2$$