Solve left(3+xright)left(3-x/2right)

$$\left( 3+x \right) \left( 3- \frac{ x }{ 2 } \right)$$

Evaluate

$$\frac{\left(6-x\right)\left(x+3\right)}{2}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2}{2}.

$$\left(3+x\right)\left(\frac{3\times 2}{2}-\frac{x}{2}\right)$$

Since \frac{3\times 2}{2} and \frac{x}{2} have the same denominator, subtract them by subtracting their numerators.

$$\left(3+x\right)\times \frac{3\times 2-x}{2}$$

Do the multiplications in 3\times 2-x.

$$\left(3+x\right)\times \frac{6-x}{2}$$

Express \left(3+x\right)\times \frac{6-x}{2} as a single fraction.

$$\frac{\left(3+x\right)\left(6-x\right)}{2}$$

Apply the distributive property by multiplying each term of 3+x by each term of 6-x.

$$\frac{18-3x+6x-x^{2}}{2}$$

Combine -3x and 6x to get 3x.

$$\frac{18+3x-x^{2}}{2}$$

Expand

$$-\frac{x^{2}}{2}+\frac{3x}{2}+9$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 3 times \frac{2}{2}.

$$\left(3+x\right)\left(\frac{3\times 2}{2}-\frac{x}{2}\right)$$

Since \frac{3\times 2}{2} and \frac{x}{2} have the same denominator, subtract them by subtracting their numerators.

$$\left(3+x\right)\times \frac{3\times 2-x}{2}$$

Do the multiplications in 3\times 2-x.

$$\left(3+x\right)\times \frac{6-x}{2}$$

Express \left(3+x\right)\times \frac{6-x}{2} as a single fraction.

$$\frac{\left(3+x\right)\left(6-x\right)}{2}$$

Apply the distributive property by multiplying each term of 3+x by each term of 6-x.

$$\frac{18-3x+6x-x^{2}}{2}$$

Combine -3x and 6x to get 3x.

$$\frac{18+3x-x^{2}}{2}$$