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3\sqrt{2}\sqrt{3}-3\left(\sqrt{2}\right)^{2}-\sqrt{3}+\sqrt{2}
Apply the distributive property by multiplying each term of 3\sqrt{2}-1 by each term of \sqrt{3}-\sqrt{2}.
3\sqrt{6}-3\left(\sqrt{2}\right)^{2}-\sqrt{3}+\sqrt{2}
To multiply \sqrt{2} and \sqrt{3}, multiply the numbers under the square root.
3\sqrt{6}-3\times 2-\sqrt{3}+\sqrt{2}
The square of \sqrt{2} is 2.
3\sqrt{6}-6-\sqrt{3}+\sqrt{2}
Multiply -3 and 2 to get -6.