Solve left(24+2right)x=24-2x6-x

$$\left( 24+2 \right) x = 24-2x6-x$$

Solve for x

$$x=-\frac{2x_{6}}{27}+\frac{8}{9}$$

Steps for Solving Linear Equation

Add 24 and 2 to get 26.

$$26x=24-2x_{6}-x$$

Add x to both sides.

$$26x+x=24-2x_{6}$$

Combine 26x and x to get 27x.

$$27x=24-2x_{6}$$

Divide both sides by 27.

$$\frac{27x}{27}=\frac{24-2x_{6}}{27}$$

Dividing by 27 undoes the multiplication by 27.

$$x=\frac{24-2x_{6}}{27}$$

Divide 24-2x_{6} by 27.

$$x=-\frac{2x_{6}}{27}+\frac{8}{9}$$

Solve for x_6

$$x_{6}=-\frac{27x}{2}+12$$

Steps for Solving Linear Equation

Add 24 and 2 to get 26.

$$26x=24-2x_{6}-x$$

Swap sides so that all variable terms are on the left hand side.

$$24-2x_{6}-x=26x$$

Subtract 24 from both sides.

$$-2x_{6}-x=26x-24$$

Add x to both sides.

$$-2x_{6}=26x-24+x$$

Combine 26x and x to get 27x.

$$-2x_{6}=27x-24$$

Divide both sides by -2.

$$\frac{-2x_{6}}{-2}=\frac{27x-24}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$x_{6}=\frac{27x-24}{-2}$$

Divide 27x-24 by -2.

$$x_{6}=-\frac{27x}{2}+12$$