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\frac{3}{2}x-1+\frac{1}{2}y-5+\frac{1}{2}=0
Subtract \frac{1}{2} from 2 to get \frac{3}{2}.
\frac{3}{2}x-6+\frac{1}{2}y+\frac{1}{2}=0
Subtract 5 from -1 to get -6.
\frac{3}{2}x-\frac{11}{2}+\frac{1}{2}y=0
Add -6 and \frac{1}{2} to get -\frac{11}{2}.
\frac{3}{2}x+\frac{1}{2}y=\frac{11}{2}
Add \frac{11}{2} to both sides. Anything plus zero gives itself.
\frac{3}{2}x=\frac{11}{2}-\frac{1}{2}y
Subtract \frac{1}{2}y from both sides.
\frac{3}{2}x=\frac{11-y}{2}
The equation is in standard form.
\frac{\frac{3}{2}x}{\frac{3}{2}}=\frac{11-y}{\frac{3}{2}\times 2}
Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.
x=\frac{11-y}{\frac{3}{2}\times 2}
Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.
x=\frac{11-y}{3}
Divide \frac{11-y}{2} by \frac{3}{2} by multiplying \frac{11-y}{2} by the reciprocal of \frac{3}{2}.
\frac{3}{2}x-1+\frac{1}{2}y-5+\frac{1}{2}=0
Subtract \frac{1}{2} from 2 to get \frac{3}{2}.
\frac{3}{2}x-6+\frac{1}{2}y+\frac{1}{2}=0
Subtract 5 from -1 to get -6.
\frac{3}{2}x-\frac{11}{2}+\frac{1}{2}y=0
Add -6 and \frac{1}{2} to get -\frac{11}{2}.
-\frac{11}{2}+\frac{1}{2}y=-\frac{3}{2}x
Subtract \frac{3}{2}x from both sides. Anything subtracted from zero gives its negation.
\frac{1}{2}y=-\frac{3}{2}x+\frac{11}{2}
Add \frac{11}{2} to both sides.
\frac{1}{2}y=\frac{11-3x}{2}
The equation is in standard form.
\frac{\frac{1}{2}y}{\frac{1}{2}}=\frac{11-3x}{\frac{1}{2}\times 2}
Multiply both sides by 2.
y=\frac{11-3x}{\frac{1}{2}\times 2}
Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.
y=11-3x
Divide \frac{-3x+11}{2} by \frac{1}{2} by multiplying \frac{-3x+11}{2} by the reciprocal of \frac{1}{2}.