Solve left(2-1/2right)x-(1-1/2)y-5+1/2=0

$$\left( 2- \frac{ 1 }{ 2 } \right) x-(1- \frac{ 1 }{ 2 } )y-5+ \frac{ 1 }{ 2 } = 0$$

Solve for x

$$x=\frac{y+9}{3}$$

Steps for Solving Linear Equation

Subtract \frac{1}{2} from 2 to get \frac{3}{2}.

$$\frac{3}{2}x-\left(1-\frac{1}{2}\right)y-5+\frac{1}{2}=0$$

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\frac{3}{2}x-\frac{1}{2}y-5+\frac{1}{2}=0$$

Add -5 and \frac{1}{2} to get -\frac{9}{2}.

$$\frac{3}{2}x-\frac{1}{2}y-\frac{9}{2}=0$$

Add \frac{1}{2}y to both sides. Anything plus zero gives itself.

$$\frac{3}{2}x-\frac{9}{2}=\frac{1}{2}y$$

Add \frac{9}{2} to both sides.

$$\frac{3}{2}x=\frac{1}{2}y+\frac{9}{2}$$

The equation is in standard form.

$$\frac{3}{2}x=\frac{y+9}{2}$$

Divide both sides of the equation by \frac{3}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{2}x}{\frac{3}{2}}=\frac{y+9}{\frac{3}{2}\times 2}$$

Dividing by \frac{3}{2} undoes the multiplication by \frac{3}{2}.

$$x=\frac{y+9}{\frac{3}{2}\times 2}$$

Divide \frac{9+y}{2} by \frac{3}{2} by multiplying \frac{9+y}{2} by the reciprocal of \frac{3}{2}.

$$x=\frac{y}{3}+3$$

Solve for y

$$y=3\left(x-3\right)$$

Steps for Solving Linear Equation

Subtract \frac{1}{2} from 2 to get \frac{3}{2}.

$$\frac{3}{2}x-\left(1-\frac{1}{2}\right)y-5+\frac{1}{2}=0$$

Subtract \frac{1}{2} from 1 to get \frac{1}{2}.

$$\frac{3}{2}x-\frac{1}{2}y-5+\frac{1}{2}=0$$

Add -5 and \frac{1}{2} to get -\frac{9}{2}.

$$\frac{3}{2}x-\frac{1}{2}y-\frac{9}{2}=0$$

Subtract \frac{3}{2}x from both sides. Anything subtracted from zero gives its negation.

$$-\frac{1}{2}y-\frac{9}{2}=-\frac{3}{2}x$$

Add \frac{9}{2} to both sides.

$$-\frac{1}{2}y=-\frac{3}{2}x+\frac{9}{2}$$

The equation is in standard form.

$$-\frac{1}{2}y=\frac{9-3x}{2}$$

Multiply both sides by -2.

$$\frac{-\frac{1}{2}y}{-\frac{1}{2}}=\frac{9-3x}{-\frac{1}{2}\times 2}$$

Dividing by -\frac{1}{2} undoes the multiplication by -\frac{1}{2}.

$$y=\frac{9-3x}{-\frac{1}{2}\times 2}$$

Divide \frac{-3x+9}{2} by -\frac{1}{2} by multiplying \frac{-3x+9}{2} by the reciprocal of -\frac{1}{2}.

$$y=3x-9$$