Solve left(2*2+3*3right)left(4*2-(-4^2right)

$$\left( 2 \cdot 2+3 \cdot 3 \right) \left( 4 \cdot 2-(- { 4 }^{ 2 } \right)$$

Evaluate

$$312$$

Solution Steps

Multiply 2 and 2 to get 4. Multiply 3 and 3 to get 9.

$$\left(4+9\right)\left(4\times 2-\left(-4^{2}\right)\right)$$

Add 4 and 9 to get 13.

$$13\left(4\times 2-\left(-4^{2}\right)\right)$$

Multiply 4 and 2 to get 8.

$$13\left(8-\left(-4^{2}\right)\right)$$

Calculate 4 to the power of 2 and get 16.

$$13\left(8-\left(-16\right)\right)$$

The opposite of -16 is 16.

$$13\left(8+16\right)$$

Add 8 and 16 to get 24.

$$13\times 24$$

Multiply 13 and 24 to get 312.

$$312$$

Factor

$$2^{3}\times 3\times 13$$