Solve left(1-1/4+3/8right)div1/8

$$\left( 1- \frac{ 1 }{ 4 } + \frac{ 3 }{ 8 } \right) \div \frac{ 1 }{ 8 }$$

Evaluate

$$9$$

Solution Steps

Convert 1 to fraction \frac{4}{4}.

$$\frac{\frac{4}{4}-\frac{1}{4}+\frac{3}{8}}{\frac{1}{8}}$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{4-1}{4}+\frac{3}{8}}{\frac{1}{8}}$$

Subtract 1 from 4 to get 3.

$$\frac{\frac{3}{4}+\frac{3}{8}}{\frac{1}{8}}$$

Least common multiple of 4 and 8 is 8. Convert \frac{3}{4} and \frac{3}{8} to fractions with denominator 8.

$$\frac{\frac{6}{8}+\frac{3}{8}}{\frac{1}{8}}$$

Since \frac{6}{8} and \frac{3}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{6+3}{8}}{\frac{1}{8}}$$

Add 6 and 3 to get 9.

$$\frac{\frac{9}{8}}{\frac{1}{8}}$$

Divide \frac{9}{8} by \frac{1}{8} by multiplying \frac{9}{8} by the reciprocal of \frac{1}{8}.

$$\frac{9}{8}\times 8$$

Cancel out 8 and 8.

$$9$$

Factor

$$3^{2}$$