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Solve for x, y
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y=\frac{2}{3}
Consider the second equation. Divide both sides by 3.
x+2\times \frac{2}{3}=1
Consider the first equation. Insert the known values of variables into the equation.
x+\frac{4}{3}=1
Multiply 2 and \frac{2}{3} to get \frac{4}{3}.
x=1-\frac{4}{3}
Subtract \frac{4}{3} from both sides.
x=-\frac{1}{3}
Subtract \frac{4}{3} from 1 to get -\frac{1}{3}.
x=-\frac{1}{3} y=\frac{2}{3}
The system is now solved.