Solve {l}{x_{1}}{x_{2}}{x_{3}}={lll}{-9}&{2}&{2}{-41/2}&{4}&{9/2}{-5}&{1}&{+1}{c}{1}{2}{-1}

$$\left( \begin{array} { l } { x _ { 1 } } \\ { x _ { 2 } } \\ { x _ { 3 } } \end{array} \right) = \left( \begin{array} { l l l } { - 9 } & { 2 } & { 2 } \\ { - \frac { 41 } { 2 } } & { 4 } & { \frac { 9 } { 2 } } \\ { - 5 } & { 1 } & { + 1 } \end{array} \right) \left( \begin{array} { c } { 1 } \\ { 2 } \\ { - 1 } \end{array} \right)$$

Solve for x_1, x_2, x_3

$$x_{1}=-7$$

$$x_{2}=-17$$

$$x_{3}=-4$$

Short Steps Using Substitution

Solve x_{3}=-4 for x_{3}.

$$x_{3}=-4$$

The system is now solved.

$$x_{1}=-7 x_{2}=-17 x_{3}=-4$$