\left( \begin{array} { l } { x - 4 } \\ { y + 2 } \end{array} \right) = \left( \begin{array} { r } { 4 } \\ { - 1 } \end{array} \right)
Solve for x, y
x=8
y=-3
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x=4+4
Consider the first equation. Add 4 to both sides.
x=8
Add 4 and 4 to get 8.
y=-1-2
Consider the second equation. Subtract 2 from both sides.
y=-3
Subtract 2 from -1 to get -3.
x=8 y=-3
The system is now solved.
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