Solve {cc}{4}&{-2}{-6}&{3}

$$\left( \begin{array} { c c } { 4 } & { - 2 } \\ { - 6 } & { 3 } \end{array} \right)$$

Calculate Determinant

$$0$$

Steps Using Diagonal Rule

Find the determinant of the matrix.

$$det(\left(\begin{matrix}4&-2\\-6&3\end{matrix}\right))$$

For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.

$$4\times 3-\left(-2\left(-6\right)\right)$$

Multiply 4 times 3.

$$12-\left(-2\left(-6\right)\right)$$

Multiply -2 times -6.

$$12-12$$

Subtract 12 from 12.

$$0$$

Evaluate

$$\left(\begin{matrix}4&-2\\-6&3\end{matrix}\right)$$