Solve {cc}{1}&{-1}{2}&{-1}{c}{1-1}{2-1}=

$$\left( \begin{array} { c c } { 1 } & { - 1 } \\ { 2 } & { - 1 } \end{array} \right) \left( \begin{array} { c } { 1 - 1 } \\ { 2 - 1 } \end{array} \right) =$$

Evaluate

$$\left(\begin{matrix}-1\\-1\end{matrix}\right)$$

Steps Using Matrix Multiplication Rule

Subtract 1 from 1 to get 0.

$$\left(\begin{matrix}1&-1\\2&-1\end{matrix}\right)\left(\begin{matrix}0\\2-1\end{matrix}\right)$$

Subtract 1 from 2 to get 1.

$$\left(\begin{matrix}1&-1\\2&-1\end{matrix}\right)\left(\begin{matrix}0\\1\end{matrix}\right)$$

Multiply each element of the first row of the first matrix by the corresponding element of the first column of the second matrix and then add these products to obtain the element in the first row, first column of the product matrix.

$$\left(\begin{matrix}-1\\\end{matrix}\right)$$

The remaining elements of the product matrix are found in the same way.

$$\left(\begin{matrix}-1\\-1\end{matrix}\right)$$

Transpose Matrix

$$\left(\begin{matrix}-1&-1\end{matrix}\right)$$