Solve left(7^-1+6^-1right)+9^-1/3^-1

$$\left( { 7 }^{ -1 } + { 6 }^{ -1 } \right) + \frac{ { 9 }^{ -1 } }{ { 3 }^{ -1 } }$$

Evaluate

$$\frac{9}{14}\approx 0.642857143$$

Solution Steps

Calculate 7 to the power of -1 and get \frac{1}{7}.

$$\frac{1}{7}+6^{-1}+\frac{9^{-1}}{3^{-1}}$$

Calculate 6 to the power of -1 and get \frac{1}{6}.

$$\frac{1}{7}+\frac{1}{6}+\frac{9^{-1}}{3^{-1}}$$

Add \frac{1}{7} and \frac{1}{6} to get \frac{13}{42}.

$$\frac{13}{42}+\frac{9^{-1}}{3^{-1}}$$

Calculate 9 to the power of -1 and get \frac{1}{9}.

$$\frac{13}{42}+\frac{\frac{1}{9}}{3^{-1}}$$

Calculate 3 to the power of -1 and get \frac{1}{3}.

$$\frac{13}{42}+\frac{\frac{1}{9}}{\frac{1}{3}}$$

Divide \frac{1}{9} by \frac{1}{3} by multiplying \frac{1}{9} by the reciprocal of \frac{1}{3}.

$$\frac{13}{42}+\frac{1}{9}\times 3$$

Multiply \frac{1}{9} and 3 to get \frac{1}{3}.

$$\frac{13}{42}+\frac{1}{3}$$

Add \frac{13}{42} and \frac{1}{3} to get \frac{9}{14}.

$$\frac{9}{14}$$

Factor

$$\frac{3 ^ {2}}{2 \cdot 7} = 0.6428571428571429$$