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\left(\sqrt{2}\right)^{2}+3\sqrt{2}-2\sqrt{2}-6
Apply the distributive property by multiplying each term of \sqrt{2}-2 by each term of \sqrt{2}+3.
2+3\sqrt{2}-2\sqrt{2}-6
The square of \sqrt{2} is 2.
2+\sqrt{2}-6
Combine 3\sqrt{2} and -2\sqrt{2} to get \sqrt{2}.
-4+\sqrt{2}
Subtract 6 from 2 to get -4.