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\left(\frac{4}{12}+\frac{3}{12}\right)\left(\frac{8}{2}+\frac{4}{3}\right)\times \frac{-8}{3}\times 6
Least common multiple of 3 and 4 is 12. Convert \frac{1}{3} and \frac{1}{4} to fractions with denominator 12.
\frac{4+3}{12}\left(\frac{8}{2}+\frac{4}{3}\right)\times \frac{-8}{3}\times 6
Since \frac{4}{12} and \frac{3}{12} have the same denominator, add them by adding their numerators.
\frac{7}{12}\left(\frac{8}{2}+\frac{4}{3}\right)\times \frac{-8}{3}\times 6
Add 4 and 3 to get 7.
\frac{7}{12}\left(4+\frac{4}{3}\right)\times \frac{-8}{3}\times 6
Divide 8 by 2 to get 4.
\frac{7}{12}\left(\frac{12}{3}+\frac{4}{3}\right)\times \frac{-8}{3}\times 6
Convert 4 to fraction \frac{12}{3}.
\frac{7}{12}\times \frac{12+4}{3}\times \frac{-8}{3}\times 6
Since \frac{12}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.
\frac{7}{12}\times \frac{16}{3}\times \frac{-8}{3}\times 6
Add 12 and 4 to get 16.
\frac{7\times 16}{12\times 3}\times \frac{-8}{3}\times 6
Multiply \frac{7}{12} times \frac{16}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{112}{36}\times \frac{-8}{3}\times 6
Do the multiplications in the fraction \frac{7\times 16}{12\times 3}.
\frac{28}{9}\times \frac{-8}{3}\times 6
Reduce the fraction \frac{112}{36} to lowest terms by extracting and canceling out 4.
\frac{28}{9}\left(-\frac{8}{3}\right)\times 6
Fraction \frac{-8}{3} can be rewritten as -\frac{8}{3} by extracting the negative sign.
\frac{28\left(-8\right)}{9\times 3}\times 6
Multiply \frac{28}{9} times -\frac{8}{3} by multiplying numerator times numerator and denominator times denominator.
\frac{-224}{27}\times 6
Do the multiplications in the fraction \frac{28\left(-8\right)}{9\times 3}.
-\frac{224}{27}\times 6
Fraction \frac{-224}{27} can be rewritten as -\frac{224}{27} by extracting the negative sign.
\frac{-224\times 6}{27}
Express -\frac{224}{27}\times 6 as a single fraction.
\frac{-1344}{27}
Multiply -224 and 6 to get -1344.
-\frac{448}{9}
Reduce the fraction \frac{-1344}{27} to lowest terms by extracting and canceling out 3.