Solve left|9-1right|div(9+1)div9+2

$$\left| 9-1 \right| \div (9+1) \div 9+2$$

Evaluate

$$\frac{94}{45}\approx 2.088888889$$

Solution Steps

Express \frac{\frac{|9-1|}{9+1}}{9} as a single fraction.

$$\frac{|9-1|}{\left(9+1\right)\times 9}+2$$

Subtract 1 from 9 to get 8.

$$\frac{|8|}{\left(9+1\right)\times 9}+2$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 8 is 8.

$$\frac{8}{\left(9+1\right)\times 9}+2$$

Add 9 and 1 to get 10.

$$\frac{8}{10\times 9}+2$$

Multiply 10 and 9 to get 90.

$$\frac{8}{90}+2$$

Reduce the fraction \frac{8}{90} to lowest terms by extracting and canceling out 2.

$$\frac{4}{45}+2$$

Convert 2 to fraction \frac{90}{45}.

$$\frac{4}{45}+\frac{90}{45}$$

Since \frac{4}{45} and \frac{90}{45} have the same denominator, add them by adding their numerators.

$$\frac{4+90}{45}$$

Add 4 and 90 to get 94.

$$\frac{94}{45}$$

Factor

$$\frac{2 \cdot 47}{3 ^ {2} \cdot 5} = 2\frac{4}{45} = 2.088888888888889$$