Solve left|5right|5+10/5left(3+3right)div3

$$\left| 5 \right| 5+ \frac{ 10 }{ 5 \left( 3+3 \right) } \div 3$$

Evaluate

$$\frac{226}{9}\approx 25.111111111$$

Solution Steps

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 5 is 5.

$$5\times 5+\frac{\frac{10}{5\left(3+3\right)}}{3}$$

Multiply 5 and 5 to get 25.

$$25+\frac{\frac{10}{5\left(3+3\right)}}{3}$$

Express \frac{\frac{10}{5\left(3+3\right)}}{3} as a single fraction.

$$25+\frac{10}{5\left(3+3\right)\times 3}$$

Add 3 and 3 to get 6.

$$25+\frac{10}{5\times 6\times 3}$$

Multiply 5 and 6 to get 30.

$$25+\frac{10}{30\times 3}$$

Multiply 30 and 3 to get 90.

$$25+\frac{10}{90}$$

Reduce the fraction \frac{10}{90} to lowest terms by extracting and canceling out 10.

$$25+\frac{1}{9}$$

Convert 25 to fraction \frac{225}{9}.

$$\frac{225}{9}+\frac{1}{9}$$

Since \frac{225}{9} and \frac{1}{9} have the same denominator, add them by adding their numerators.

$$\frac{225+1}{9}$$

Add 225 and 1 to get 226.

$$\frac{226}{9}$$

Factor

$$\frac{2 \cdot 113}{3 ^ {2}} = 25\frac{1}{9} = 25.11111111111111$$