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5-3\sqrt{27}-2
The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -5 is 5.
5-3\times 3\sqrt{3}-2
Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.
5-9\sqrt{3}-2
Multiply -3 and 3 to get -9.
3-9\sqrt{3}
Subtract 2 from 5 to get 3.