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Integrate w.r.t. j
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det(\left(\begin{matrix}2&j&k\\3&-1&-2\\1&2&-1\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}2&j&k&2&j\\3&-1&-2&3&-1\\1&2&-1&1&2\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
2\left(-1\right)\left(-1\right)+j\left(-2\right)+k\times 3\times 2=2+6k-2j
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-k+2\left(-2\right)\times 2-3j=-3j-k-8
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
2+6k-2j-\left(-3j-k-8\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
j+7k+10
Subtract -k-8-3j from 2-2j+6k.
det(\left(\begin{matrix}2&j&k\\3&-1&-2\\1&2&-1\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
2det(\left(\begin{matrix}-1&-2\\2&-1\end{matrix}\right))-jdet(\left(\begin{matrix}3&-2\\1&-1\end{matrix}\right))+kdet(\left(\begin{matrix}3&-1\\1&2\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
2\left(-\left(-1\right)-2\left(-2\right)\right)-j\left(3\left(-1\right)-\left(-2\right)\right)+k\left(3\times 2-\left(-1\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
2\times 5-j\left(-1\right)+k\times 7
Simplify.
j+7k+10
Add the terms to obtain the final result.