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det(\left(\begin{matrix}15&-6&4\\19&4&-3\\46&1&6\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}15&-6&4&15&-6\\19&4&-3&19&4\\46&1&6&46&1\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
15\times 4\times 6-6\left(-3\right)\times 46+4\times 19=1264
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
46\times 4\times 4-3\times 15+6\times 19\left(-6\right)=7
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
1264-7
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
1257
Subtract 7 from 1264.
det(\left(\begin{matrix}15&-6&4\\19&4&-3\\46&1&6\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
15det(\left(\begin{matrix}4&-3\\1&6\end{matrix}\right))-\left(-6det(\left(\begin{matrix}19&-3\\46&6\end{matrix}\right))\right)+4det(\left(\begin{matrix}19&4\\46&1\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
15\left(4\times 6-\left(-3\right)\right)-\left(-6\left(19\times 6-46\left(-3\right)\right)\right)+4\left(19-46\times 4\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
15\times 27-\left(-6\times 252\right)+4\left(-165\right)
Simplify.
1257
Add the terms to obtain the final result.