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det(\left(\begin{matrix}1&-16&19\\7&-6&13\\9&6&4\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&-16&19&1&-16\\7&-6&13&7&-6\\9&6&4&9&6\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-6\times 4-16\times 13\times 9+19\times 7\times 6=-1098
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
9\left(-6\right)\times 19+6\times 13+4\times 7\left(-16\right)=-1396
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-1098-\left(-1396\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
298
Subtract -1396 from -1098.
det(\left(\begin{matrix}1&-16&19\\7&-6&13\\9&6&4\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}-6&13\\6&4\end{matrix}\right))-\left(-16det(\left(\begin{matrix}7&13\\9&4\end{matrix}\right))\right)+19det(\left(\begin{matrix}7&-6\\9&6\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-6\times 4-6\times 13-\left(-16\left(7\times 4-9\times 13\right)\right)+19\left(7\times 6-9\left(-6\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-102-\left(-16\left(-89\right)\right)+19\times 96
Simplify.
298
Add the terms to obtain the final result.