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det(\left(\begin{matrix}-3&4&16\\5&5&13\\-4&3&12\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-3&4&16&-3&4\\5&5&13&5&5\\-4&3&12&-4&3\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-3\times 5\times 12+4\times 13\left(-4\right)+16\times 5\times 3=-148
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-4\times 5\times 16+3\times 13\left(-3\right)+12\times 5\times 4=-197
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-148-\left(-197\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
49
Subtract -197 from -148.
det(\left(\begin{matrix}-3&4&16\\5&5&13\\-4&3&12\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-3det(\left(\begin{matrix}5&13\\3&12\end{matrix}\right))-4det(\left(\begin{matrix}5&13\\-4&12\end{matrix}\right))+16det(\left(\begin{matrix}5&5\\-4&3\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-3\left(5\times 12-3\times 13\right)-4\left(5\times 12-\left(-4\times 13\right)\right)+16\left(5\times 3-\left(-4\times 5\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-3\times 21-4\times 112+16\times 35
Simplify.
49
Add the terms to obtain the final result.