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det(\left(\begin{matrix}-3&-3&-11\\2&-3&8\\1&-4&-7\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-3&-3&-11&-3&-3\\2&-3&8&2&-3\\1&-4&-7&1&-4\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-3\left(-3\right)\left(-7\right)-3\times 8-11\times 2\left(-4\right)=1
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-3\left(-11\right)-4\times 8\left(-3\right)-7\times 2\left(-3\right)=171
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
1-171
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-170
Subtract 171 from 1.
det(\left(\begin{matrix}-3&-3&-11\\2&-3&8\\1&-4&-7\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-3det(\left(\begin{matrix}-3&8\\-4&-7\end{matrix}\right))-\left(-3det(\left(\begin{matrix}2&8\\1&-7\end{matrix}\right))\right)-11det(\left(\begin{matrix}2&-3\\1&-4\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-3\left(-3\left(-7\right)-\left(-4\times 8\right)\right)-\left(-3\left(2\left(-7\right)-8\right)\right)-11\left(2\left(-4\right)-\left(-3\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-3\times 53-\left(-3\left(-22\right)\right)-11\left(-5\right)
Simplify.
-170
Add the terms to obtain the final result.