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det(\left(\begin{matrix}11&21&31\\12&22&32\\13&23&33\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}11&21&31&11&21\\12&22&32&12&22\\13&23&33&13&23\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
11\times 22\times 33+21\times 32\times 13+31\times 12\times 23=25278
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
13\times 22\times 31+23\times 32\times 11+33\times 12\times 21=25278
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
25278-25278
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
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Subtract 25278 from 25278.
det(\left(\begin{matrix}11&21&31\\12&22&32\\13&23&33\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
11det(\left(\begin{matrix}22&32\\23&33\end{matrix}\right))-21det(\left(\begin{matrix}12&32\\13&33\end{matrix}\right))+31det(\left(\begin{matrix}12&22\\13&23\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
11\left(22\times 33-23\times 32\right)-21\left(12\times 33-13\times 32\right)+31\left(12\times 23-13\times 22\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
11\left(-10\right)-21\left(-20\right)+31\left(-10\right)
Simplify.
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Add the terms to obtain the final result.