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det(\left(\begin{matrix}1&1&1\\4&1&2\\0&1&6\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&1&1&1&1\\4&1&2&4&1\\0&1&6&0&1\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
6+4=10
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
2+6\times 4=26
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
10-26
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-16
Subtract 26 from 10.
det(\left(\begin{matrix}1&1&1\\4&1&2\\0&1&6\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}1&2\\1&6\end{matrix}\right))-det(\left(\begin{matrix}4&2\\0&6\end{matrix}\right))+det(\left(\begin{matrix}4&1\\0&1\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
6-2-4\times 6+4
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
4-24+4
Simplify.
-16
Add the terms to obtain the final result.