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det(\left(\begin{matrix}i&j&k\\4&-5&6\\-3&-5&9\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}i&j&k&i&j\\4&-5&6&4&-5\\-3&-5&9&-3&-5\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-5i\times 9+j\times 6\left(-3\right)+k\times 4\left(-5\right)=-45i-20k-18j
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-3\left(-5\right)k-5\times \left(6i\right)+9\times 4j=36j+15k-30i
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-45i-20k-18j-\left(36j+15k-30i\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-15i-35k-54j
Subtract 15k-30i+36j from -45i-18j-20k.
det(\left(\begin{matrix}i&j&k\\4&-5&6\\-3&-5&9\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
idet(\left(\begin{matrix}-5&6\\-5&9\end{matrix}\right))-jdet(\left(\begin{matrix}4&6\\-3&9\end{matrix}\right))+kdet(\left(\begin{matrix}4&-5\\-3&-5\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
i\left(-5\times 9-\left(-5\times 6\right)\right)-j\left(4\times 9-\left(-3\times 6\right)\right)+k\left(4\left(-5\right)-\left(-3\left(-5\right)\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-15i-j\times 54+k\left(-35\right)
Simplify.
-15i-35k-54j
Add the terms to obtain the final result.