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det(\left(\begin{matrix}4&4&2\\-5&3&-2\\10&-2&-3\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}4&4&2&4&4\\-5&3&-2&-5&3\\10&-2&-3&10&-2\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
4\times 3\left(-3\right)+4\left(-2\right)\times 10+2\left(-5\right)\left(-2\right)=-96
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
10\times 3\times 2-2\left(-2\right)\times 4-3\left(-5\right)\times 4=136
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-96-136
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-232
Subtract 136 from -96.
det(\left(\begin{matrix}4&4&2\\-5&3&-2\\10&-2&-3\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
4det(\left(\begin{matrix}3&-2\\-2&-3\end{matrix}\right))-4det(\left(\begin{matrix}-5&-2\\10&-3\end{matrix}\right))+2det(\left(\begin{matrix}-5&3\\10&-2\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
4\left(3\left(-3\right)-\left(-2\left(-2\right)\right)\right)-4\left(-5\left(-3\right)-10\left(-2\right)\right)+2\left(-5\left(-2\right)-10\times 3\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
4\left(-13\right)-4\times 35+2\left(-20\right)
Simplify.
-232
Add the terms to obtain the final result.