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det(\left(\begin{matrix}4&-10&2\\-10&14&26\\2&26&-34\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}4&-10&2&4&-10\\-10&14&26&-10&14\\2&26&-34&2&26\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
4\times 14\left(-34\right)-10\times 26\times 2+2\left(-10\right)\times 26=-2944
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
2\times 14\times 2+26\times 26\times 4-34\left(-10\right)\left(-10\right)=-640
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-2944-\left(-640\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-2304
Subtract -640 from -2944.
det(\left(\begin{matrix}4&-10&2\\-10&14&26\\2&26&-34\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
4det(\left(\begin{matrix}14&26\\26&-34\end{matrix}\right))-\left(-10det(\left(\begin{matrix}-10&26\\2&-34\end{matrix}\right))\right)+2det(\left(\begin{matrix}-10&14\\2&26\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
4\left(14\left(-34\right)-26\times 26\right)-\left(-10\left(-10\left(-34\right)-2\times 26\right)\right)+2\left(-10\times 26-2\times 14\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
4\left(-1152\right)-\left(-10\times 288\right)+2\left(-288\right)
Simplify.
-2304
Add the terms to obtain the final result.