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det(\left(\begin{matrix}1&-8&3\\2&13&-1\\-1&8&-1\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&-8&3&1&-8\\2&13&-1&2&13\\-1&8&-1&-1&8\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
13\left(-1\right)-8\left(-1\right)\left(-1\right)+3\times 2\times 8=27
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-13\times 3+8\left(-1\right)-2\left(-8\right)=-31
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
27-\left(-31\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
58
Subtract -31 from 27.
det(\left(\begin{matrix}1&-8&3\\2&13&-1\\-1&8&-1\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}13&-1\\8&-1\end{matrix}\right))-\left(-8det(\left(\begin{matrix}2&-1\\-1&-1\end{matrix}\right))\right)+3det(\left(\begin{matrix}2&13\\-1&8\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
13\left(-1\right)-8\left(-1\right)-\left(-8\left(2\left(-1\right)-\left(-\left(-1\right)\right)\right)\right)+3\left(2\times 8-\left(-13\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-5-\left(-8\left(-3\right)\right)+3\times 29
Simplify.
58
Add the terms to obtain the final result.