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det(\left(\begin{matrix}1&-18&-11\\3&6&-4\\13&8&3\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}1&-18&-11&1&-18\\3&6&-4&3&6\\13&8&3&13&8\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
6\times 3-18\left(-4\right)\times 13-11\times 3\times 8=690
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
13\times 6\left(-11\right)+8\left(-4\right)+3\times 3\left(-18\right)=-1052
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
690-\left(-1052\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
1742
Subtract -1052 from 690.
det(\left(\begin{matrix}1&-18&-11\\3&6&-4\\13&8&3\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
det(\left(\begin{matrix}6&-4\\8&3\end{matrix}\right))-\left(-18det(\left(\begin{matrix}3&-4\\13&3\end{matrix}\right))\right)-11det(\left(\begin{matrix}3&6\\13&8\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
6\times 3-8\left(-4\right)-\left(-18\left(3\times 3-13\left(-4\right)\right)\right)-11\left(3\times 8-13\times 6\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
50-\left(-18\times 61\right)-11\left(-54\right)
Simplify.
1742
Add the terms to obtain the final result.