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det(\left(\begin{matrix}-7&7&9\\2&-1&-5\\7&-7&-9\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-7&7&9&-7&7\\2&-1&-5&2&-1\\7&-7&-9&7&-7\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-7\left(-1\right)\left(-9\right)+7\left(-5\right)\times 7+9\times 2\left(-7\right)=-434
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
7\left(-1\right)\times 9-7\left(-5\right)\left(-7\right)-9\times 2\times 7=-434
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-434-\left(-434\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
0
Subtract -434 from -434.
det(\left(\begin{matrix}-7&7&9\\2&-1&-5\\7&-7&-9\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-7det(\left(\begin{matrix}-1&-5\\-7&-9\end{matrix}\right))-7det(\left(\begin{matrix}2&-5\\7&-9\end{matrix}\right))+9det(\left(\begin{matrix}2&-1\\7&-7\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-7\left(-\left(-9\right)-\left(-7\left(-5\right)\right)\right)-7\left(2\left(-9\right)-7\left(-5\right)\right)+9\left(2\left(-7\right)-7\left(-1\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-7\left(-26\right)-7\times 17+9\left(-7\right)
Simplify.
0
Add the terms to obtain the final result.