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det(\left(\begin{matrix}-2&-4&-6\\-8&-2&0\\2&-4&6\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-2&-4&-6&-2&-4\\-8&-2&0&-8&-2\\2&-4&6&2&-4\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-2\left(-2\right)\times 6-6\left(-8\right)\left(-4\right)=-168
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
2\left(-2\right)\left(-6\right)+6\left(-8\right)\left(-4\right)=216
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-168-216
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-384
Subtract 216 from -168.
det(\left(\begin{matrix}-2&-4&-6\\-8&-2&0\\2&-4&6\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-2det(\left(\begin{matrix}-2&0\\-4&6\end{matrix}\right))-\left(-4det(\left(\begin{matrix}-8&0\\2&6\end{matrix}\right))\right)-6det(\left(\begin{matrix}-8&-2\\2&-4\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-2\left(-2\right)\times 6-\left(-4\left(-8\right)\times 6\right)-6\left(-8\left(-4\right)-2\left(-2\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-2\left(-12\right)-\left(-4\left(-48\right)\right)-6\times 36
Simplify.
-384
Add the terms to obtain the final result.