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det(\left(\begin{matrix}-1&2&4\\-2&3&9\\-5&-2&2\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-1&2&4&-1&2\\-2&3&9&-2&3\\-5&-2&2&-5&-2\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-3\times 2+2\times 9\left(-5\right)+4\left(-2\right)\left(-2\right)=-80
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-5\times 3\times 4-2\times 9\left(-1\right)+2\left(-2\right)\times 2=-50
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-80-\left(-50\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-30
Subtract -50 from -80.
det(\left(\begin{matrix}-1&2&4\\-2&3&9\\-5&-2&2\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-det(\left(\begin{matrix}3&9\\-2&2\end{matrix}\right))-2det(\left(\begin{matrix}-2&9\\-5&2\end{matrix}\right))+4det(\left(\begin{matrix}-2&3\\-5&-2\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-\left(3\times 2-\left(-2\times 9\right)\right)-2\left(-2\times 2-\left(-5\times 9\right)\right)+4\left(-2\left(-2\right)-\left(-5\times 3\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-24-2\times 41+4\times 19
Simplify.
-30
Add the terms to obtain the final result.