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det(\left(\begin{matrix}-1&-2&-1\\1&1&-2\\-2&-3&-3\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}-1&-2&-1&-1&-2\\1&1&-2&1&1\\-2&-3&-3&-2&-3\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
-\left(-3\right)-2\left(-2\right)\left(-2\right)-\left(-3\right)=-2
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
-2\left(-1\right)-3\left(-2\right)\left(-1\right)-3\left(-2\right)=2
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
-2-2
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-4
Subtract 2 from -2.
det(\left(\begin{matrix}-1&-2&-1\\1&1&-2\\-2&-3&-3\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
-det(\left(\begin{matrix}1&-2\\-3&-3\end{matrix}\right))-\left(-2det(\left(\begin{matrix}1&-2\\-2&-3\end{matrix}\right))\right)-det(\left(\begin{matrix}1&1\\-2&-3\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
-\left(-3-\left(-3\left(-2\right)\right)\right)-\left(-2\left(-3-\left(-2\left(-2\right)\right)\right)\right)-\left(-3-\left(-2\right)\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
-\left(-9\right)-\left(-2\left(-7\right)\right)-\left(-1\right)
Simplify.
-4
Add the terms to obtain the final result.