Solve left|left|left|-6/4+5/-2right|*2right|/2right|

$$\left| \frac{ \left| \left| \frac{ -6 }{ 4 } + \frac{ 5 }{ -2 } \right| \times 2 \right| }{ 2 } \right|$$

Evaluate

$$4$$

Solution Steps

Reduce the fraction \frac{-6}{4} to lowest terms by extracting and canceling out 2.

$$|\frac{||-\frac{3}{2}+\frac{5}{-2}|\times 2|}{2}|$$

Fraction \frac{5}{-2} can be rewritten as -\frac{5}{2} by extracting the negative sign.

$$|\frac{||-\frac{3}{2}-\frac{5}{2}|\times 2|}{2}|$$

Since -\frac{3}{2} and \frac{5}{2} have the same denominator, subtract them by subtracting their numerators.

$$|\frac{||\frac{-3-5}{2}|\times 2|}{2}|$$

Subtract 5 from -3 to get -8.

$$|\frac{||\frac{-8}{2}|\times 2|}{2}|$$

Divide -8 by 2 to get -4.

$$|\frac{||-4|\times 2|}{2}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -4 is 4.

$$|\frac{|4\times 2|}{2}|$$

Multiply 4 and 2 to get 8.

$$|\frac{|8|}{2}|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 8 is 8.

$$|\frac{8}{2}|$$

Divide 8 by 2 to get 4.

$$|4|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of 4 is 4.

$$4$$

Factor

$$2^{2}$$