\left\{ \begin{array}{l}{ z = - 2 }\\{ - 3 y + 4 z = 4 }\end{array} \right.
Solve for z, y
y=-4
z=-2
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\left\{ \begin{array}{l}{ z = - 2 }\\{ - 3 y + 4 z = 4 }\end{array} \right.
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-3y+4\left(-2\right)=4
Consider the second equation. Insert the known values of variables into the equation.
-3y-8=4
Multiply 4 and -2 to get -8.
-3y=4+8
Add 8 to both sides.
-3y=12
Add 4 and 8 to get 12.
y=\frac{12}{-3}
Divide both sides by -3.
y=-4
Divide 12 by -3 to get -4.
z=-2 y=-4
The system is now solved.
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