\left\{ \begin{array} { r } { y = 12 } \\ { 2 x - y = 4 } \end{array} \right.
Solve for y, x
x=8
y=12
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\left\{ \begin{array} { r } { y = 12 } \\ { 2 x - y = 4 } \end{array} \right.
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2x-12=4
Consider the second equation. Insert the known values of variables into the equation.
2x=4+12
Add 12 to both sides.
2x=16
Add 4 and 12 to get 16.
x=\frac{16}{2}
Divide both sides by 2.
x=8
Divide 16 by 2 to get 8.
y=12 x=8
The system is now solved.
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